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Self-adjoint operator
... }$ is the complement of D( A ) ; a self-adjoint operator if A = A † and $\; ... † . So, if a bounded linear operator is self-adjoint , it is represented by a Hermitian matrix in any orthonormal ...
Wiki article - Anonymous (not verified) - 26/10/2015 - 17:56 - 0 comments
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Projector
... Q 2 have the following properties: They are self-adjoint ; Their eigenspaces are H 1 and H 2 ... have the following Definition: The linear, bounded, self-adjoint, idempotent operators Q 1 and Q 2 on ...
Wiki article - Anonymous (not verified) - 26/10/2015 - 17:56 - 0 comments
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Operators
... an observable A must be a linear, self-adjoint and positive operator . In particular, A must be ... chosen to compute them; whereas A must be a self-adjoint operator to guarantee the reality, and thus the physical ...
Wiki article - Anonymous (not verified) - 26/10/2015 - 17:56 - 0 comments
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Symmetric operator
... linear operator is symmetric, it is also a Hermitian and self-adjoint operator . Category:Mathematical Structure ...
Wiki article - Anonymous (not verified) - 26/10/2015 - 17:56 - 0 comments
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Hermitian matrix
... be the representation, in a given orthonormal basis, of a self-adjoint operator . Properties of Hermitian matrices For two ...
Wiki article - Anonymous (not verified) - 26/10/2015 - 17:56 - 0 comments
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Density matrix
... that the description of quantum mechanics in which all self-adjoint operator s represent observables is untenable. For this reason, ...
Wiki article - Anonymous (not verified) - 08/09/2020 - 13:08 - 0 comments
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Hilbert spaces
... V . Theorem . The orthogonal projection P V is a self-adjoint linear operator on H of norm ≤ 1 with the property P V 2 = P V . Moreover, any self-adjoint linear operator E such that E 2 = E is of the form P V ...
Wiki article - Anonymous (not verified) - 26/10/2015 - 17:56 - 0 comments
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Bell's theorem
... formalism , observables X , Y are represented as self-adjoint operator s on a Hilbert space . To compute the correlation, ... system. The spin observables are represented by the 2 × 2 self-adjoint matrices: $$S_x = \begin{bmatrix} 0 & 1 \\ 1 & 0 ...
Wiki article - Anonymous (not verified) - 26/10/2015 - 17:37 - 0 comments
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Bloch sphere
... i A is a local homeomorphism from the space of self-adjoint complex matrices to U( n ). The space of self-adjoint complex matrices has real dimension n 2. Corollary . The ...
Wiki article - Anonymous (not verified) - 26/10/2015 - 17:56 - 0 comments
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Positive operator
... space is necessarily a symmetric operator and has a self-adjoint extension that is also a positive operator. The set of ...
Wiki article - Anonymous (not verified) - 26/10/2015 - 17:56 - 0 comments